Optimal. Leaf size=76 \[ \frac{A+3 i B}{4 a^2 d (1+i \tan (c+d x))}-\frac{x (B+i A)}{4 a^2}-\frac{A+i B}{4 d (a+i a \tan (c+d x))^2} \]
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Rubi [A] time = 0.130703, antiderivative size = 76, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 32, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.094, Rules used = {3590, 3526, 8} \[ \frac{A+3 i B}{4 a^2 d (1+i \tan (c+d x))}-\frac{x (B+i A)}{4 a^2}-\frac{A+i B}{4 d (a+i a \tan (c+d x))^2} \]
Antiderivative was successfully verified.
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Rule 3590
Rule 3526
Rule 8
Rubi steps
\begin{align*} \int \frac{\tan (c+d x) (A+B \tan (c+d x))}{(a+i a \tan (c+d x))^2} \, dx &=-\frac{A+i B}{4 d (a+i a \tan (c+d x))^2}-\frac{i \int \frac{a (A+i B)+2 a B \tan (c+d x)}{a+i a \tan (c+d x)} \, dx}{2 a^2}\\ &=\frac{A+3 i B}{4 a^2 d (1+i \tan (c+d x))}-\frac{A+i B}{4 d (a+i a \tan (c+d x))^2}-\frac{(i A+B) \int 1 \, dx}{4 a^2}\\ &=-\frac{(i A+B) x}{4 a^2}+\frac{A+3 i B}{4 a^2 d (1+i \tan (c+d x))}-\frac{A+i B}{4 d (a+i a \tan (c+d x))^2}\\ \end{align*}
Mathematica [A] time = 0.53058, size = 92, normalized size = 1.21 \[ \frac{\sec ^2(c+d x) ((-4 A d x-i A+4 i B d x+B) \sin (2 (c+d x))+(4 i A d x+A+B (4 d x+i)) \cos (2 (c+d x))-4 i B)}{16 a^2 d (\tan (c+d x)-i)^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.03, size = 162, normalized size = 2.1 \begin{align*}{\frac{A}{4\,{a}^{2}d \left ( \tan \left ( dx+c \right ) -i \right ) ^{2}}}+{\frac{{\frac{i}{4}}B}{{a}^{2}d \left ( \tan \left ( dx+c \right ) -i \right ) ^{2}}}-{\frac{{\frac{i}{4}}A}{{a}^{2}d \left ( \tan \left ( dx+c \right ) -i \right ) }}+{\frac{3\,B}{4\,{a}^{2}d \left ( \tan \left ( dx+c \right ) -i \right ) }}-{\frac{\ln \left ( \tan \left ( dx+c \right ) -i \right ) A}{8\,{a}^{2}d}}+{\frac{{\frac{i}{8}}\ln \left ( \tan \left ( dx+c \right ) -i \right ) B}{{a}^{2}d}}+{\frac{A\ln \left ( \tan \left ( dx+c \right ) +i \right ) }{8\,{a}^{2}d}}-{\frac{{\frac{i}{8}}B\ln \left ( \tan \left ( dx+c \right ) +i \right ) }{{a}^{2}d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.42338, size = 154, normalized size = 2.03 \begin{align*} \frac{{\left ({\left (-4 i \, A - 4 \, B\right )} d x e^{\left (4 i \, d x + 4 i \, c\right )} + 4 i \, B e^{\left (2 i \, d x + 2 i \, c\right )} - A - i \, B\right )} e^{\left (-4 i \, d x - 4 i \, c\right )}}{16 \, a^{2} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.05259, size = 167, normalized size = 2.2 \begin{align*} \begin{cases} \frac{\left (16 i B a^{2} d e^{4 i c} e^{- 2 i d x} + \left (- 4 A a^{2} d e^{2 i c} - 4 i B a^{2} d e^{2 i c}\right ) e^{- 4 i d x}\right ) e^{- 6 i c}}{64 a^{4} d^{2}} & \text{for}\: 64 a^{4} d^{2} e^{6 i c} \neq 0 \\x \left (\frac{i A + B}{4 a^{2}} - \frac{\left (i A e^{4 i c} - i A + B e^{4 i c} - 2 B e^{2 i c} + B\right ) e^{- 4 i c}}{4 a^{2}}\right ) & \text{otherwise} \end{cases} + \frac{x \left (- i A - B\right )}{4 a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.34941, size = 147, normalized size = 1.93 \begin{align*} \frac{\frac{2 \,{\left (A - i \, B\right )} \log \left (-i \, \tan \left (d x + c\right ) + 1\right )}{a^{2}} - \frac{2 \,{\left (A - i \, B\right )} \log \left (-i \, \tan \left (d x + c\right ) - 1\right )}{a^{2}} + \frac{3 \, A \tan \left (d x + c\right )^{2} - 3 i \, B \tan \left (d x + c\right )^{2} - 10 i \, A \tan \left (d x + c\right ) + 6 \, B \tan \left (d x + c\right ) - 3 \, A - 5 i \, B}{a^{2}{\left (\tan \left (d x + c\right ) - i\right )}^{2}}}{16 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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